for instance, if the user enters number 4 ..the program should display:
1
22
333
4444
* I did solve this Q:
#include%26lt;iostream.h%26gt;
void main() {
int n;
cin%26gt;%26gt;n;
for(int i=1;i%26lt;=n;i++)
{
for(int j=0;i+j%26lt;=n;j++)
cout%26lt;%26lt;i;
cout%26lt;%26lt;"\n";
}
}
}
But when i run it on the compiler ... it gave this output
1111
222
33
4
Can someone help plz..
Write a c++ program that prompt the user to enter a number and then display a series of numbers as follows:?
Change
for(int j=0;i+j%26lt;=n;j++)
to
for(int j=1;j%26lt;=i;j++)
Reply:#include %26lt;stdio.h%26gt;
#include %26lt;conio.h%26gt;
void main()
{
int i,j,k,x;
clrscr();
printf(" Enter A Num : ");
scanf("%d",%26amp;x);
k=1;
for(i=1;i%26lt;=x;i++)
{
for(j=1;j%26lt;=i;j++)
printf("%d",k);
printf("\n");
k++;
}
getch();
} Report It
Reply:#include%26lt;iostream.h%26gt;
#include%26lt;conio.h%26gt;
void main()
{
int n;
cout%26lt;%26lt;"enter the number\n";
cin%26gt;%26gt;n;
for(int i=1;i%26lt;=n;i++)
{
for(int j=1;j%26lt;=i;j++)
cout%26lt;%26lt;i;
cout%26lt;%26lt;"\n";
}
getch();
}
Reply:... wtf is that?
hawthorn
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